A 0.1 M solution of weak acid HA is 1% dissociated at 25^(@)C To this solution NaA is added till [NaA] = 0.2 M, if the new degree of dissociation of HA = yxx 10^(-5) then what is 'y'?

A 0.1 M solution of weak acid HA is 1% dissociated at 25^(@)C To this

1.	A 0.1 M solution of weak acid HA is 1% dissociated at 25^(@)C To this solution NaA is added till [NaA] = 0.2 M, if the new degree of dissociation of HA = yxx 10^(-5) then what is 'y'?
Answer» Solution :` alpha = 0.01 , C =0.1` ` K_a = CALPHA ^(2)= 0.1 xx ( 0.01 )^(2)= 10 ^(5) ` ` K_a = ([H^(+) ] [A^(-) ]) /( [HA]) =([H^(+) ]xx 0.2 )/(0.1 )` ` RARR [H^(+) ] = calpha =10 ^(-5)xx ( 0.1)/( 0.2 ) rArr alpha = 5 xx 10 ^(-5)`