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(a) 0.456 g of a metal gives 0.606 g of its chloride. Calculate the equivalent mass of the metal (b)Calculate the equivalent mass of potassium dichromate. The reduction half-reaction in acid medium is,Cr_(2)O_(7)^(2-)+14H^(+)+6e^(-) rarr 2Cr^(3+)+7H_(2)O

Answer» <html><body><p></p>Solution :Mass of the <a href="https://interviewquestions.tuteehub.com/tag/metal-1094457" style="font-weight:bold;" target="_blank" title="Click to know more about METAL">METAL</a> = `W_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)` = 0.456 g.<br/>Mass of the metal chloride = `W_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)` = 0.606 g<br/>`:.` Mass of chlorine = `W_(2) -W_(1)` = 0.606 - 0.456 = 0.15 g<br/>0.15 g of chlorine combine with 0.456 g of metal. <br/>`:.` 35.46 g of chlorine will combine with`0.456/0.15 xx 35.46` = 107.79 g `<a href="https://interviewquestions.tuteehub.com/tag/eq-446394" style="font-weight:bold;" target="_blank" title="Click to know more about EQ">EQ</a> ^(-1)`. <br/>`Cr_(2)O_(7)^(2-)+14H^(+)+6e^(-) rarr 2Cr^(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>+)+7H_(2)O`<br/>Equivalent mass = `("Molar mass")/("No. of electrons gained")`<br/>`:.` Molar mass of `K_(2)Cr_(2)O_(7)` = 294.18<br/>`:.` Equivalent mass of `K_(2)Cr_(2)O_(7) = 294.18/6 = 49.03`</body></html>


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