A 0.5 g sample containing MnO_(2) is treated with HCl liberating Cl_(2). The Cl_(2) is passed into a solution of KI and 30.0 cm^(3) of 0.1 M Na_(2)S_(2)O_(3) are required to tirate the liberated iodine. Calculate the percentage of MnO_(2) in the sample.

A 0.5 g sample containing MnO_(2) is treated with HCl liberating Cl_(2

1.	A 0.5 g sample containing MnO_(2) is treated with HCl liberating Cl_(2). The Cl_(2) is passed into a solution of KI and 30.0 cm^(3) of 0.1 M Na_(2)S_(2)O_(3) are required to tirate the liberated iodine. Calculate the percentage of MnO_(2) in the sample.
Answer» <html><body><p><br/></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`<a href="https://interviewquestions.tuteehub.com/tag/30-304807" style="font-weight:bold;" target="_blank" title="Click to know more about 30">30</a>.0 mL 0.1 M Na_(2)S_(2)O_(<a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a>)-=30.0 mL 0.1 N Na_(2)S_(2)O_(3)` <br/> `-=30.0 mL 0.1 N I_(2)` <br/> `-=30.0 mL 0.1 N Cl_(2)` <br/> `-=30.0 mL 0.1 N MnO_(2)` <br/> Amount of `MnO_(2)` present `=(NxxExxV)/(<a href="https://interviewquestions.tuteehub.com/tag/1000-265236" style="font-weight:bold;" target="_blank" title="Click to know more about 1000">1000</a>)` <br/> `=(1)/(10)xx(87)/(2)xx(30)/(1000)` <br/> `% MnO_(2)=(87xx30xx100)/(10xx2xx1000xx0.5)=26.1`</body></html>