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A 0.50 g H_(2)SO_(4) is dissolve in 0.25 L solution, so find out the normality and molarity respectively of the solution. (H=1, S= 32, O=16) |
Answer» <html><body><p>0.040, 0.020<br/> 0.4, 0.2<br/>0.020, 0.040<br/> 0.2, 0.4</p>Solution :Molarity `=("Mass of <a href="https://interviewquestions.tuteehub.com/tag/solute-1217068" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTE">SOLUTE</a>(gm)")/("<a href="https://interviewquestions.tuteehub.com/tag/moleculer-2840274" style="font-weight:bold;" target="_blank" title="Click to know more about MOLECULER">MOLECULER</a> weight of solute" xx "<a href="https://interviewquestions.tuteehub.com/tag/volume-728707" style="font-weight:bold;" target="_blank" title="Click to know more about VOLUME">VOLUME</a> of solution(<a href="https://interviewquestions.tuteehub.com/tag/litre-1075864" style="font-weight:bold;" target="_blank" title="Click to know more about LITRE">LITRE</a>)")` <br/> `= (0.50)/(98xx0.5) = 0.020` <br/> `N= Mxx2 = 0.020xx2= 0.040`</body></html> | |