A 1.10 g sample of copper ore is dissolved and the Cu^(2+)is treated with excess KI. The liberated I_2requires 12.12 mL of 0.10M Na_(2) S_(2)O_3solution for titration. Find the % of copper by mass in ore.

A 1.10 g sample of copper ore is dissolved and the Cu^(2+)is treated w

1.	A 1.10 g sample of copper ore is dissolved and the Cu^(2+)is treated with excess KI. The liberated I_2requires 12.12 mL of 0.10M Na_(2) S_(2)O_3solution for titration. Find the % of copper by mass in ore.
Answer» <html><body><p><br/></p>Solution :`Cu^(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>+) +erarrCu^(+), 2I^(-) rarrI_(2)+<a href="https://interviewquestions.tuteehub.com/tag/2e-300683" style="font-weight:bold;" target="_blank" title="Click to know more about 2E">2E</a>` <br/> Meq.of `Cu^(+2)` = Meq.of liberated `I_2` <br/> = Meq.of `Na_(2)S_2O_3` <br/> `= 12.12 xx0.1 <a href="https://interviewquestions.tuteehub.com/tag/xx1-1463705" style="font-weight:bold;" target="_blank" title="Click to know more about XX1">XX1</a> =1.212` <br/> `:.(W_(cu^(2+)))/(63.6//1)xx1000=1.212` <br/> ` :. W_(cu) =W_(cu^(2+))=0.077` <br/> `( :. Cuoverset(H_2SO_4)rarrCuSO_(<a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a>))` <br/> `:. %Cu=(0.077)/(1.10)<a href="https://interviewquestions.tuteehub.com/tag/xx100-3292680" style="font-weight:bold;" target="_blank" title="Click to know more about XX100">XX100</a> =7%`</body></html>