A 1 M solution of glucose reaches dissociation equilibrium according to equation given below 6HCHOhArrC_(16)H_(12)O_(6). What is the concentration of HCHO at equilibrium constant is 6xx10^(22)

A 1 M solution of glucose reaches dissociation equilibrium according t

1.	A 1 M solution of glucose reaches dissociation equilibrium according to equation given below 6HCHOhArrC_(16)H_(12)O_(6). What is the concentration of HCHO at equilibrium constant is 6xx10^(22)
Answer» <html><body><p>`<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>.6xx10^(8)`M<br/>`3.2xx10^(6)`M<br/>`3.2xx10^(-4)`M<br/>`1.6xx10^(-4)`M</p>Solution :`6HCHOhArrC_(6)H_(<a href="https://interviewquestions.tuteehub.com/tag/12-269062" style="font-weight:bold;" target="_blank" title="Click to know more about 12">12</a>)O_(6)` forward <a href="https://interviewquestions.tuteehub.com/tag/reaction-22747" style="font-weight:bold;" target="_blank" title="Click to know more about REACTION">REACTION</a> <br/> `C_(6)H_(12)O_(6)hArr 6HCHO` backward reaction <br/> `K_(2) = [(1)/(K_(1))]^(1//6)` , `K_(2) = [(1)/(6xx10^(22))]^(1//6)` <br/>`K_(2) = 1.6xx10^(-4)` M</body></html>