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A 1 M solution of glucose reaches dissociation equilibrium according to equation given below 6HCHOhArrC_(16)H_(12)O_(6). What is the concentration of HCHO at equilibrium constant is 6xx10^(22) |
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Answer» `1.6xx10^(8)`M `C_(6)H_(12)O_(6)hArr 6HCHO` backward reaction `K_(2) = [(1)/(K_(1))]^(1//6)` , `K_(2) = [(1)/(6xx10^(22))]^(1//6)` `K_(2) = 1.6xx10^(-4)` M |
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