1.

A 10 cm column of air is trapped by a column of mercury, 8 cm long, in a capillary tubehorizontally fixed as shown below, at 1 atm pressure. When the tube is held atcertain angle theta^@ with open end up, the weight of Hg is borne partially by the gas. Vertical Height of Hg is a measure of additional pressure on gas. When the tube's held at 45^@ with the horizontal with open end up the length of air column is

Answer»

`(76 xx 10)/(76 + 8/(sqrt2)) cm`
`(76 xx 8/(sqrt2))/(76 + 10) cm`
`76 xx 8/(sqrt2)`
`10 xx 8/(sqrt2)`

SOLUTION :At `45^@C`, pressure on GAS = `76 + h COS THETA`
`= 76 + 8/(sqrt(2))`
`P_1l_1 = P_2l_2 , 76 xx 10 = (76 + 8/(sqrt2))l_2`.


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