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A 10 kg object collides with a stationary 5 kg object and after collision, they stick together and move forward with velocity 4 ms^(-1). What is the velocity with which the 10 kg object hits the second one ? |
Answer» <html><body><p>`4 <a href="https://interviewquestions.tuteehub.com/tag/ms-549331" style="font-weight:bold;" target="_blank" title="Click to know more about MS">MS</a>^(-1)`<br/>`<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a> ms^(-1)`<br/>`10 ms^(-1)`<br/>`12ms^(-1)`</p>Solution :Here `m_1 = 10 kg, m_2 = <a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a> kg, u_1 = ? , u_2 = 0, <a href="https://interviewquestions.tuteehub.com/tag/v-722631" style="font-weight:bold;" target="_blank" title="Click to know more about V">V</a> = 4 m//s` <br/> Applying the principle of conservation of linear momentum, <br/> `m_1u_1 + m_2u_2 = (m_1 + m_2)v , 10 u_1+ 5 xx 0 = (10 + 5) 4` <br/> `10 u_1 = 60 " or " u_1 = 60/10 = 6 ms^(-1)`.</body></html> | |