A `10 muF` capacitor is charged to a potential difference of `50 V` and is connected to another uncharged capacitor in parallel. Now the common potential difference becomes `20` volt. The capacitance of second capacitor isA. `10muF`B. `20muF`C. `30muF`D. `15muF`

A `10 muF` capacitor is charged to a potential difference of `50 V` an

1.	A `10 muF` capacitor is charged to a potential difference of `50 V` and is connected to another uncharged capacitor in parallel. Now the common potential difference becomes `20` volt. The capacitance of second capacitor isA. `10muF`B. `20muF`C. `30muF`D. `15muF`
Answer» Correct Answer - D Charge of first capacitor, `q=CV = 10xx50=500muC` Common potentail `=("Total charge")/("Total capacitance")` `20=(500)/(C_(1)+C_(2)) rArr 20 =(500)/(10+C_(2))` `C_(2)=15muF`

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A `10 muF` capacitor is charged to a potential difference of `50 V` and is connected to another uncharged capacitor in parallel. Now the common potential difference becomes `20` volt. The capacitance of second capacitor isA. `10muF`B. `20muF`C. `30muF`D. `15muF`

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