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A 100 ml mixture of Na_(2)CO_(3) and NaHCO_(3) is tittrated against 1 M HCl. If v_(1)L and v_(2)L are consumed when phenolphthalein and methyl orange are used as indicators respectively in two separate titrations, which of the following is true form molarities in the original solution.

Answer» <html><body><p>molarity of `Na_(2)CO_(3)=20v_(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>)`<br/>molarity of `NaHCO_(3)=10(v_(2)-2v_(1))`<br/>molarity of `Na_(2)CO_(3)=10(v_(2)+v_(1))` <br/>molarity of `NaHCO_(3)=10(v_(2)-v_(1))` </p>Solution :When HPh <a href="https://interviewquestions.tuteehub.com/tag/used-2318798" style="font-weight:bold;" target="_blank" title="Click to know more about USED">USED</a> <br/> `(1)/(2)xx` Eqts of `Na_(2)CO_(3)` = Eq of HCl <br/> `(1)/(2)xx(<a href="https://interviewquestions.tuteehub.com/tag/100-263808" style="font-weight:bold;" target="_blank" title="Click to know more about 100">100</a>)/(1000)xxM_(Na_(2)CO_(3))xx2=V_(1)xx1` <br/> `M_(NC_(2)CO_(3))=10V_(1)......(1)` <br/> When meOH used <br/> Eqts of `NC_(2)CO_(3)+` Eqts of `NaHCO_(3)` = Eq of HCl <br/> `((100)/(1000)xxM_(Na_(2)CO_(3))xx2)+((100)/(1000)xxM_(NCHCO_(3))xx1)=V_(2)xx1....(2)` <br/> On solving (1), (2) <br/> `M_(NaHCO_(3))=10(V_(2)-2V_(1))`</body></html>


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