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A 2 lit solution contains 0.04 mol of each of [CO(NH_(3))_(5)SO_(4)]Br and [CO(NH_(3))_(5)Br]SO_(4). To 1 lit of this solution, excess of AgNO_(3) is added. To the remaining solution of excen of BaCl_(2) is added. The amounts of precipitated salts, respectively, are |
| Answer» <html><body><p>0.01 mol & 0.01 mol <<a href="https://interviewquestions.tuteehub.com/tag/br-390993" style="font-weight:bold;" target="_blank" title="Click to know more about BR">BR</a>>0.01 mol & 0.02 mol <br/>0.02 mol & 0.01 mol <br/>0.02 mol & 0.02 mol</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Given that 2L solution contains 0.04 mol each of `[CO(NH_(3))_(6)SO_(4)]Br and [CO(NH_(3))_(5)Br]SO_(4)`. Therefore, the concentration is 0.02 mol `"<a href="https://interviewquestions.tuteehub.com/tag/lit-537267" style="font-weight:bold;" target="_blank" title="Click to know more about LIT">LIT</a>"^(-1)`. <br/> `underset("0.02 mol")([CO(NH_(3))_(5)SO_(4)]Br)underset("0.02 mol0.02 mol")(rarrBr+[CO(NH_(4))_(5)SO_(4)]^(+))` <br/> `underset("0.02 mol")([CO(NH_(3))_(5)Br]SO_(4))underset("0.02 mol ")(rarrSO_(4)^(-2))+underset("0.02 mol")([CO(NH_(3))_(5)Br]^(+2))` <br/> `underset(("<a href="https://interviewquestions.tuteehub.com/tag/excess-978535" style="font-weight:bold;" target="_blank" title="Click to know more about EXCESS">EXCESS</a>"))(<a href="https://interviewquestions.tuteehub.com/tag/ag-362275" style="font-weight:bold;" target="_blank" title="Click to know more about AG">AG</a>^(+))+underset((0.02))(Br^(-))rarrunderset(0.02)(AgBr)` <br/> `underset(("excess"))(Ba^(+2))+underset((0.02))(SO_(4)^(-2))rarrunderset(0.02)(BaSO_(4))`</body></html> | |