A 20 litre container at 400 K contains CO_2(g) at pressure 0.4 atm and an excess of SrO (neglect the volume of solid SrO). The volume of the container is now decreased by moving the mavable piston fitted in the container. The maximumvolume of the conatiner, when pressure of CO_2 attains its maximum value will be : Give that : SrCO_3 (s)hArr SrO(s) + CO_2(g) K_p = 1.6 atm

A 20 litre container at 400 K contains CO_2(g) at pressure 0.4 atm and

1.	A 20 litre container at 400 K contains CO_2(g) at pressure 0.4 atm and an excess of SrO (neglect the volume of solid SrO). The volume of the container is now decreased by moving the mavable piston fitted in the container. The maximumvolume of the conatiner, when pressure of CO_2 attains its maximum value will be : Give that : SrCO_3 (s)hArr SrO(s) + CO_2(g) K_p = 1.6 atm
Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>><a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a> litre<br/>5 litre <br/>10 litre<br/>4 litre</p>Solution :Given that `K_p = 1.6 atm` <br/> `V_1 = 20 L, V_2 = ?, T_1 = 400 K , T_2 = <a href="https://interviewquestions.tuteehub.com/tag/400k-315702" style="font-weight:bold;" target="_blank" title="Click to know more about 400K">400K</a>` <br/> `K_P = P_(CO_2)`<br/> `:. P_(CO_2) = 1.6 atm` <br/> `P_1 = 0.4 atm` <br/> `P_2= 1.6 atm` <br/> `(P_1V_1)/T_1= (P_2V_2)/T_2` <br/> `:. V_2 = (P_1V_1)/T_1 xx T_2/P_2 =(0.4 atm xx 20L)/(cancel 400K) xx (cancel400K)/(1.6atm) = <a href="https://interviewquestions.tuteehub.com/tag/5l-326334" style="font-weight:bold;" target="_blank" title="Click to know more about 5L">5L</a>`</body></html>