InterviewSolution
Saved Bookmarks
InterviewSolution
| 1. |
A 20 mL mixture of ethane, ethylene, and CO_2 is heated with O_2. After the explosion, there was a contraction of 28 mL and after treatment with KOH, there was a further contraction of 30 mL. What is the composition of the mixture? |
| Answer» <html><body><p><<a href="https://interviewquestions.tuteehub.com/tag/p-588962" style="font-weight:bold;" target="_blank" title="Click to know more about P">P</a>></p>Solution :Let the volume of ethane, ethylene, and `CO_(<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>)`, respectively, are a,b and `(20-a-b)mL` <br/> Now contraction after cooling`=28mL` <br/> `thereforeV_(R)-V_(P)=25` <br/> `V_(R)=` Volume of `C_(2)H_(6)+` volume of `C_(2)H_(4)+` volume of `CO_(2)+` volume of `O_(2)` used for combustion <br/> `V_(P)=` volume of `CO_(2)` produced (Volume of `H_(2)O` is not taken <a href="https://interviewquestions.tuteehub.com/tag/since-644476" style="font-weight:bold;" target="_blank" title="Click to know more about SINCE">SINCE</a> it condenses) <br/> Considering the combustion <a href="https://interviewquestions.tuteehub.com/tag/gases-13668" style="font-weight:bold;" target="_blank" title="Click to know more about GASES">GASES</a>. <br/> (a). `C_(2)H_(6)+(7)/(2)O_(2)to2CO_(2)+3H_(2)O` <br/> (b). `C_(2)H_(4)+3O_(2)to2CO_(2)+2H_(2)O` <br/> (c). `CO_(2)to` no <a href="https://interviewquestions.tuteehub.com/tag/reaction-22747" style="font-weight:bold;" target="_blank" title="Click to know more about REACTION">REACTION</a> <br/> `V_(R)=(a+(7)/(2)a)+(b+3b)+(20-a-b)` <br/> `V_(P)=(2a+2b)+(20-a-b)` <br/> `V_(P)-V_(R)=(5)/(2)a+2b=28` <br/> `therefore5a+4b=56`..(i) <br/> There is a further contraction of 32 mL on treatment with KOH. Volume of `CO_(2)` produced `+` Volume of `CO_(2)` original <br/> `=32` <br/> `(2a+2b)+(20-a-b)=32` <br/> `therefore a+b=12`...(ii) <br/> On solving (i) and (ii) we get <br/> `a=8mL` (volume of `C_(2)H_(6))` <br/> `b=4mL` (Volume of `C_(2)H_(4))` <br/> Volume of `CO_(2)=8mL`</body></html> | |