A 25.0 mLof 0.1 M weak acid HA is titrated with 0.1 M NaOH to the equivalence point. If the pH at the equivalence point is 8.28 Calculate K_(a) for this acid

A 25.0 mLof 0.1 M weak acid HA is titrated with 0.1 M NaOH to the equi

1.	A 25.0 mLof 0.1 M weak acid HA is titrated with 0.1 M NaOH to the equivalence point. If the pH at the equivalence point is 8.28 Calculate K_(a) for this acid
Answer» <html><body><p>`2.8 xx 10^(-4)`<br/>`1.3 xx 10^(-4)`<br/>`5.2 xx 10^(-9)`<br/>`1.9 xx 10^(-<a href="https://interviewquestions.tuteehub.com/tag/6-327005" style="font-weight:bold;" target="_blank" title="Click to know more about 6">6</a>)`</p>Solution :At equivalence point, it is the hydrolysis of <a href="https://interviewquestions.tuteehub.com/tag/salt-1193804" style="font-weight:bold;" target="_blank" title="Click to know more about SALT">SALT</a> of weak acid and strong base <br/> `pH = 7 + 1/(2)pKa + 1/2 "<a href="https://interviewquestions.tuteehub.com/tag/log-543719" style="font-weight:bold;" target="_blank" title="Click to know more about LOG">LOG</a>" <a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>`</body></html>