A 4% solution (w/w) of sucrose (M 342 g `mol^(-1)`) in water has a freezing point of 271.15K Calculate the freezing point of 5% glucose (M= 180 g `mol^(-1)`) in water. (Given: Freezing point of pure water 273.15 K)

A 4% solution (w/w) of sucrose (M 342 g `mol^(-1)`) in water has a fre

1.	A 4% solution (w/w) of sucrose (M 342 g `mol^(-1)`) in water has a freezing point of 271.15K Calculate the freezing point of 5% glucose (M= 180 g `mol^(-1)`) in water. (Given: Freezing point of pure water 273.15 K)
Answer» Mass of sucrose `(W_(B))4` g Mass of water `(W_(A))=100-4= 96 g` `M_(B)=342` `DeltaT_(f)=273.15-271.5=2K` `K_(f)=(DeltaT_(f)xxM_(B)xxW_(A))/(W_(B)xx1000)` `K_(f)=(2xx342xx96)/(4xx1000)=16.416` Now, for solution of glcose Mass of glucose (WB)= 5g Mass of water (WA) =100 -5 =95 `M_(B)=180gmol^(-1)` `DeltaT_(f)=(K_(f)xxW_(B)xx1000)/(M_(B)xxW_(A))=(16.416xx5xx1000)/(180xx95)=4.8 K` `DeltaT_(f)=T_(f)^(@)-T_(f)=4.8=273.15-Tf` `T_(f)=273.15-4.8=268.35K`

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A 4% solution (w/w) of sucrose (M 342 g `mol^(-1)`) in water has a freezing point of 271.15K Calculate the freezing point of 5% glucose (M= 180 g `mol^(-1)`) in water. (Given: Freezing point of pure water 273.15 K)

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