1.

A 50 ml solution of pH = 1 mixed with 50 ml solution of pH = 2. What will be the pH of the mixture ?

Answer»


Solution :In the MIXTURE, `[H^(+)]=((10^(-1)+10^(-2)))/(2) = (0.11)/(2) = 0.055=5.5xx10^(-2)`
`pH = - LOG (5.5xx10^(-2))=2 - 0.74 = 1.26`


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