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A 60mL mixture of nitrous oxide and nitric oxide is totally decomposed. The volume of the mixture after passing through alkaline pyogallol is 48mL. Calculate the weight percentage of the diatomic oxide in the

Answer» <html><body><p></p>Solution :The balanced equations for the <a href="https://interviewquestions.tuteehub.com/tag/decomposition-946042" style="font-weight:bold;" target="_blank" title="Click to know more about DECOMPOSITION">DECOMPOSITION</a> of <a href="https://interviewquestions.tuteehub.com/tag/nitrous-2196967" style="font-weight:bold;" target="_blank" title="Click to know more about NITROUS">NITROUS</a> oxide `(N_(2)O)` and nitric oxide (NO) are given as <br/>`N_(2)O to N_(2)+(1)/(2)O_(2),NOto(1)/(2)N_(2)+(1)/(2)O_(2)` <br/> The volume of mixture initially = 60mL <br/> Let the volume of `N_(2)O` in the initial mixture =<a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a> <br/> Volume of `N_(2)O` in the initial mixture =60-x <br/> The volume of nitrogen finally =48mL <br/> `60-x+(x)/(2)=48` <br/> The <a href="https://interviewquestions.tuteehub.com/tag/ratio-13379" style="font-weight:bold;" target="_blank" title="Click to know more about RATIO">RATIO</a> of <a href="https://interviewquestions.tuteehub.com/tag/moles-1100459" style="font-weight:bold;" target="_blank" title="Click to know more about MOLES">MOLES</a> of NO:NO = ratio of volumes = 24:36 = 2:3 <br/> Ratio of weights =2 x 30:3x44=5:11 <br/> Weight percentage of No`=(5)/(16)x100=31.25%`</body></html>


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