InterviewSolution
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InterviewSolution
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(a) A cell is prepared by dipping a zinc rod in 1M zinc sulphate solution and a silver electrode in 1M silver nitrate solution. The standard electrode potential given : `E^(@)Zn_(2+1//Zn) = -0.76V, E^(@)A_(g+//)A_(g) = +0.80V` What is the effect of increase in concentration of `Zn^(2+) " on the " E_(cell)` ? (b) Write the products of electrolysis of aqueous solution of NaCI with platinum electrodes. (c) Calculate e.m.f. of the following cell at 298 K: `"Ni(s)"//"Ni"^(2+)(0.01M)////"Cu"^(2+)(0.1M)//"Cu(s)"` `["Given"E_(Ni2+//Ni)^(@) = -0.025 V E_(Cu2+//Cu)^(@) = +0.34V]` Write the overall cell reaction. |
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Answer» (a) `E_(cell) " decreases."` (b) `"Anode" : CI_(2)uarr` `"Cathode" : H_(2)uarr` (c) `Cu^(2+)(aq) + Ni(s) to Ni^(2+)(aq) + Cu(s)` `E_(cell)^(@) = E_("cathode")^(@) - E_("anode")^(@)` `E_(cell)^(@) = 0.34-(-0.25)` `E_(cell)^(@) =0.59V` `E_(cell)^(@) =E_(cell)^(@)-(2.303RT)/(nF) "log" ([Ni^(2+)])/([Cu^(2+)])` `E_(cell)^(@) = 0.59 - (059)/(2)"log" ([0.01])/([0.1])` `E_(cell) =0.6195V` |
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