InterviewSolution
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InterviewSolution
| 1. |
(a) A monoenergetic electron beam with electron speed of 5.20 × 106m/s is subject to a magnetic field of 1.30 × 10–4 Tnormal to the beam velocity. What is the radius of the circle tracedby the beam, given e/m for electron equals 1.76 × 1011C /kg (b) Is the formula you employ in (a) valid for calculating radius ofthe path of a 20 MeV electron beam? If not, in what way is itmodified?[Note: Exercises 11.20(b) and 11.21 (b) take you to relativisticmechanics which is beyond the scope of this book. They have beeninserted here simply to emphasise the point that the formulas youuse in part (a) of the exercises are not valid at very high speeds orenergies. See answers at the end to know what ‘very high speed orenergy’ means.] |
| Answer» (a) A monoenergetic electron beam with electron speed of 5.20 × 106m/s is subject to a magnetic field of 1.30 × 10–4 Tnormal to the beam velocity. What is the radius of the circle tracedby the beam, given e/m for electron equals 1.76 × 1011C /kg (b) Is the formula you employ in (a) valid for calculating radius ofthe path of a 20 MeV electron beam? If not, in what way is itmodified?[Note: Exercises 11.20(b) and 11.21 (b) take you to relativisticmechanics which is beyond the scope of this book. They have beeninserted here simply to emphasise the point that the formulas youuse in part (a) of the exercises are not valid at very high speeds orenergies. See answers at the end to know what ‘very high speed orenergy’ means.] | |