A alkayl halide with molecular formula C_(6)H_(13)Br on dehydrohalogenation gave two isomeric alkenes X and Y with molecular formula C_(6)H_(12). On reductive ozonolysis, X and Y gave four compounds CH_(3)COCH_(3), CH_(3)CHO, CH_(3)CH_(2)CHO and (CH_(3))_(2) CHCHO. Find the alkyl halide.

A alkayl halide with molecular formula C_(6)H_(13)Br on dehydrohalogen

1.	A alkayl halide with molecular formula C_(6)H_(13)Br on dehydrohalogenation gave two isomeric alkenes X and Y with molecular formula C_(6)H_(12). On reductive ozonolysis, X and Y gave four compounds CH_(3)COCH_(3), CH_(3)CHO, CH_(3)CH_(2)CHO and (CH_(3))_(2) CHCHO. Find the alkyl halide.
Answer» Solution :(i) `C_(6)H_(13)BR` is a 3-Bromo-4 METHYLPENTANE.`CH_(3) - UNDERSET(underset(CH_(3))(\|))(CH)- underset(underset(H)(\|))overset(overset(Br)(\|))(C) - CH_(2) - CH_(3)` (ii) 3-Bromo-4 methylpentane on dehydrogenation GIVE two isomers X and Y as follows: Therefore `C_(6)H_(13)Br` is 3-Bromo-4- methylpentane.