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(a) Assign orientation to the three chlorotoluenes with mu = 1.3, 1.78 and 1.9 D (b) Assign orientation to the three cholornitrobenzenes with mu = 2.5, 3.4 and 4.3 D (c ) Which has higher mu . |
Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`mu` of (I) <a href="https://interviewquestions.tuteehub.com/tag/gt-1013864" style="font-weight:bold;" target="_blank" title="Click to know more about GT">GT</a> (III) (i) Bromobenzene (II) is resonance stabillised due to delocalisation of `lp e^(-')s` of the Br <a href="https://interviewquestions.tuteehub.com/tag/atom-887280" style="font-weight:bold;" target="_blank" title="Click to know more about ATOM">ATOM</a> in the benzene ring The `(C -B)` bond acquires some double bond character, while in (I) is a single bond, since it does not undergo resonance In other words, the `(C -Br)` bond in (II) is shorter than that in <br/> (ii) Due to more s-character `sp^(2)` hybridised `C` is more `EN` `sp^(3)` hybrid `C` atom, therefore the `sp^(2)` hybrid `C` of the `(C -Br)` bond in (II) has less tendency `C` atom of (I) As a <a href="https://interviewquestions.tuteehub.com/tag/result-1187343" style="font-weight:bold;" target="_blank" title="Click to know more about RESULT">RESULT</a>, the `(C -Br)` bond in (I) is more polar than in (II) i e the magnitude of negative charge (`delta`-) is more on Br atom of (I) than in (II) Therefore `mu` of `(I) gt (II)` [since `mu = q xx d` (charge `xx` distance)] <br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/KSV_INORG_CHM_P1_C02_S01_024_S01.png" width="80%"/><br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/KSV_INORG_CHM_P1_C02_S01_024_S02.png" width="80%"/><br/> <img src="https://d10lpgp6xz60nq.cloudfront.net/physics_images/KSV_INORG_CHM_P1_C02_S01_024_S03.png" width="80%"/></body></html> | |