InterviewSolution
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InterviewSolution
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`A, B` and `C` are parallel conductors of equal length carrying currents `I, I` and `2I` respectively. Distance between `A` and `B` is `x`. Distance between `B` and `C` is also `x`. `F_(1)` is the force exerted by `B` on `A` and `F_(2)` is the force exerted by `B` on `A` choose the correct answer A. `F_(1)=2F_(2)`B. `F_(2)=2F_(1)`C. `F_(1)=F_(2)`D. `F_(1)=-F_(2)` |
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Answer» Correct Answer - D `F=(mu_(0))/(4pi)(2i_(1)i_(2))/(a)` `F_(1)=(mu_(0))/(4pi)=(2i^(2))/(x)` (Attraction) `F_(2)=(mu_(0))/(4pi)=(2ixx2i)/(2x)=(mu_(0))/(4pi)(2i^(2))/(x)` (Repulsion) Thus `F_(1)=-F_(2)` |
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