A+B hArr C+D is 100. If intially the concentrations of A and B are equal but at equilibrium concentration of D will be twicethatof A, then whatwill be the equilibrium constantof the reaction ?

A+B hArr C+D is 100. If intially the concentrations of A and B are equ

1.	A+B hArr C+D is 100. If intially the concentrations of A and B are equal but at equilibrium concentration of D will be twicethatof A, then whatwill be the equilibrium constantof the reaction ?
Answer» <html><body><p>`4//9`<br/>`018`<br/>`017`<br/>`0*11`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> : `{:(,A,+,B,hArr,<a href="https://interviewquestions.tuteehub.com/tag/c-7168" style="font-weight:bold;" target="_blank" title="Click to know more about C">C</a>,D,),(" Intial",a,,a,,,,),(" At eqm",(a-x),,(a-x),,x,,x):}` <br/> But we are given that `x= <a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a> (a-x)`<br/>or` 3 x = 2 a or a=3/2x = 1.5 x ` <br/> ` :. K= (x xx x)/(a-x^(2))= x^(2)/(1.5 x - x)^(2) = x^(2)/(0.25 x^(2))=4`</body></html>