A + B rarr C+D, Delta H = -10,000 J mol^(-1) , Delta S = - 33.3 J mol^(-1) K^(-1) (i) At what temperature the reaction will occur spontaneously from leftto right ? (ii) At what temperature , the reaction will reverse?

A + B rarr C+D, Delta H = -10,000 J mol^(-1) , Delta S = - 33.3 J mol^

1.	A + B rarr C+D, Delta H = -10,000 J mol^(-1) , Delta S = - 33.3 J mol^(-1) K^(-1) (i) At what temperature the reaction will occur spontaneously from leftto right ? (ii) At what temperature , the reaction will reverse?
Answer» Solution :`DELTA G = DeltaH -T DeltaS` At EQUILIBRIUM , `Delta G =0` so that `Delta H = T Delta S` or `T = (DeltaH)/(DeltaS) = (- 10000J mol^(-1))/( - 33.3JK^(-1)mol^(-1))= 300.3K` (i) For spontaneity from left to right, `Delta G` should be -ve for the GIVEN REACTION. This willbe so if `T lt 300.3K` ( becasue `Delta H` and `Delta S` both are -ve ) (ii) For reverse reaction to occur, `Delta G` shouldbe `+` be for forward reaction. This will be so if `Tgt300.3` K.