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A ball falling with velocity `vecv_(i)=(-0.65hati-0.35hatj)ms^(-1)` is subjected to a net impulse `vecI=(0.6hati+0.18hatj)` Ns. If the ball has a mass of `0.275kg` calculate its velocity immediately following the impulse .

Answer» `mvecv_(f)-mvecv_(i) = vecI, vecv_(f)=vecv_(i) +(vecI)/(m)`
`vecv_(f) =-0.65hati-0.35hatj+(0.6hati+0.18hatj)/(0.275)`
`vecv_(f) =-0.65hati-0.35hatj+2.18hati+0.655hatj`
`vecv_(f) =(1.53hati +0.305hatj)ms^(-1)` .


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