

InterviewSolution
Saved Bookmarks
1. |
A ball is dropped from a height of 20 m. At the same instant another ball is thrown up from the ground with a speed of 20 m/s. When and where will theballs meet? |
Answer» <html><body><p>Choose a <a href="https://interviewquestions.tuteehub.com/tag/frame-998974" style="font-weight:bold;" target="_blank" title="Click to know more about FRAME">FRAME</a> of reference in which the ball thrown upwards is stationary. In other words <a href="https://interviewquestions.tuteehub.com/tag/imagine-2727769" style="font-weight:bold;" target="_blank" title="Click to know more about IMAGINE">IMAGINE</a> what it wouldlook like if you were observing from a point on the upward travelling ball. At the <a href="https://interviewquestions.tuteehub.com/tag/start-1224710" style="font-weight:bold;" target="_blank" title="Click to know more about START">START</a> you would be stationary, you would <a href="https://interviewquestions.tuteehub.com/tag/see-630247" style="font-weight:bold;" target="_blank" title="Click to know more about SEE">SEE</a> the other ball <a href="https://interviewquestions.tuteehub.com/tag/initially-516121" style="font-weight:bold;" target="_blank" title="Click to know more about INITIALLY">INITIALLY</a> moving towards you at 20m/s and it would accelerate at g. Use the equations of uniformly accelerated motion (suvat) to find the time it takes for a collision. (s=ut + 1/2 at^2) In this time the upward travelling ball will have covered a distance given by: dist =speed x time =20 x t. This is how far from the floor the collision takes place.Explanation:</p></body></html> | |