A ball is fallen freely from top of tower of height 100 m and another ball is thrown upwards with 50 m/s at the same time when they will cross each other ? (g = 10 m//s^(2))

A ball is fallen freely from top of tower of height 100 m and another

1.	A ball is fallen freely from top of tower of height 100 m and another ball is thrown upwards with 50 m/s at the same time when they will cross each other ? (g = 10 m//s^(2))
Answer» <html><body><p>1 s <br/>2 s <br/><a href="https://interviewquestions.tuteehub.com/tag/3-301577" style="font-weight:bold;" target="_blank" title="Click to know more about 3">3</a> s <br/><a href="https://interviewquestions.tuteehub.com/tag/4-311707" style="font-weight:bold;" target="_blank" title="Click to know more about 4">4</a> s </p>Solution :For the ball falling freely `v _(<a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>) = 0, d = 100 m` <br/> `therefore` <a href="https://interviewquestions.tuteehub.com/tag/distance-116" style="font-weight:bold;" target="_blank" title="Click to know more about DISTANCE">DISTANCE</a> covered in .t. time <br/> `d _(1) = v _(0)t + 1/2 g t^(2)` <br/> `d _(1) = 0 + 1/2 (10) t ^(2) = 5t ^(2) ""…(1)` <br/> Initial velocity of the ball thrown upwards is `v _(0).=50m//s` and it meets the first ball at `(100 -d _(1)`)m distance <br/> `therefore 100 -d _(1) = v _(0) .t = 1/2 g t ^(2)` <br/> `therefore 100 - d _(1) = 50 t - 1/2 (10) t ^(2) `<br/> `therefore 100 -d _(1) = 50 t -5t ^(2)` <br/> From equation (1), <br/> `therefore 100-5t ^(2) = 59 t - 5t ^(2)` <br/> `therefore 50 t = 100` <br/> `therefore t = (100)/(50)` <br/> `therefore t =2s`</body></html>