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A ball moving with a velocity of 6 m/s strikes an identical stationary ball. After collisions each ball moves at an angle of 30^(@)with the original line of motion. What are the speeds of the balls after the collision?

Answer» <html><body><p></p>Solution :<img src="https://doubtnut-static.s.llnwi.net/static/physics_images/AKS_ELT_AI_PHY_XI_V01_B_C04_SLV_025_S01.png" width="80%"/> <br/> <a href="https://interviewquestions.tuteehub.com/tag/applying-1982651" style="font-weight:bold;" target="_blank" title="Click to know more about APPLYING">APPLYING</a> the law of conservation of momentum perpendicular to the initial <a href="https://interviewquestions.tuteehub.com/tag/line-1074199" style="font-weight:bold;" target="_blank" title="Click to know more about LINE">LINE</a> of motion: <br/> `0 = mv _(1) sin 30^(@) - mv _(2) sin 30^(@) or v _(1) =v _(2) …(i)` <br/> <a href="https://interviewquestions.tuteehub.com/tag/hence-484344" style="font-weight:bold;" target="_blank" title="Click to know more about HENCE">HENCE</a> speed of both will be same after collision. Now <a href="https://interviewquestions.tuteehub.com/tag/along-1974109" style="font-weight:bold;" target="_blank" title="Click to know more about ALONG">ALONG</a> the line of motion: <br/> `mv = mv _(1) cos 30^(@) + mv _(2) cos 30^(@).....(ii)` <br/> Putting <a href="https://interviewquestions.tuteehub.com/tag/equation-974081" style="font-weight:bold;" target="_blank" title="Click to know more about EQUATION">EQUATION</a> (i) in equation (ii) <br/> `mv = 2 mv _(1) cos 30^(@) (or) v _(1) = (v)/(sqrt3) = (6)/(sqrt3) = 2 sqrt3 m//s`</body></html>


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