1.

A bivalent metal has an equivalent mass of 32. The molecular mass of the metal nitrate is

Answer»

168
192
188
182

Solution :Given, equivalent MASS of bivalent METAL `M^(2+)=32`
`:.` Atomic mass of `MM = 32 xx 2 = 64`
The metal nitrate formed has the formula `M(NO_(3))_(2)`
`:.` Molecular mass of the metal nitrate `= 64+28+96=188`


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