A block A of mass M moving with speed u collides elastically with block B of mass m which is connected to block C of mass m with a spring. When the compression in spring is maximum, the velocity of block C with respect to block A is (Neglect the friction everywhere)

A block A of mass M moving with speed u collides elastically with bloc

1.	A block A of mass M moving with speed u collides elastically with block B of mass m which is connected to block C of mass m with a spring. When the compression in spring is maximum, the velocity of block C with respect to block A is (Neglect the friction everywhere)
Answer» <html><body><p><a href="https://interviewquestions.tuteehub.com/tag/zero-751093" style="font-weight:bold;" target="_blank" title="Click to know more about ZERO">ZERO</a><br/>`(M/(M+m))u`<br/>`(m/(M+m))u`<br/>`(m/M)u`</p>Solution :`v_(A) = (M-m)/(M+m) u and v_(B) = (<a href="https://interviewquestions.tuteehub.com/tag/2mu-1837999" style="font-weight:bold;" target="_blank" title="Click to know more about 2MU">2MU</a>)/(M+m)` <br/> Velocity of C at maximum <a href="https://interviewquestions.tuteehub.com/tag/compression-20610" style="font-weight:bold;" target="_blank" title="Click to know more about COMPRESSION">COMPRESSION</a> = `v_(B)/<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>` <br/> `v_(c) = 1/2[(2M)/(M+m)]u = (M/(M+m))u` <br/> `v_(CA) = v_(C)-v_(A) = (m/(M+m))u`</body></html>