A block C of mass m is moving with velocity `v_(0)` and collides elastically with block A of mass m and connected to another block B of mass `2m` through spring constant k. What is k if `x_(0)` is compression of spring when velocity of A and B is same? A. `(mv_(0)^(2))/(x_(0)^(2))`B. `(mv_(0)^(2))/(2x_(0)^(2))`C. `(3mv_(0)^(2))/(2x_(0)^(2))`D. `(2mv_(0)^(2))/(3x_(0)^(2))`

A block C of mass m is moving with velocity `v_(0)` and collides elast

1.	A block C of mass m is moving with velocity `v_(0)` and collides elastically with block A of mass m and connected to another block B of mass `2m` through spring constant k. What is k if `x_(0)` is compression of spring when velocity of A and B is same? A. `(mv_(0)^(2))/(x_(0)^(2))`B. `(mv_(0)^(2))/(2x_(0)^(2))`C. `(3mv_(0)^(2))/(2x_(0)^(2))`D. `(2mv_(0)^(2))/(3x_(0)^(2))`
Answer» Correct Answer - D Their common velocity would be when C strikes A, A accquires the velocity of C and C beocmes stationary. A forces B to move and ultimately both acquires common velocity with spring compressed by `x_(0)`. `v=(mv_(0)/(m+2m)` = `v_(0)/3)` Now applying conservation of mechanical energy `1/2mv_(0)^(2)=1/2kx_(0)^(2) + 1/2(3m)(v_(0)/3)^(2) rArr k = 2/3(mv_(0)^(2)/(x_(0)^(2)`

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