A block of mass 15 kg is placed on a long trolley . The coefficient of friction between the block andthe trolley is 0.18. The trolley accelerates from rest with 0.5ms^(-2) for 20s and then moves with uniform velocity. Discuss the motion of theblock as viewed by (a) a stationary observer on theground (b) as observer moving with the trolley.

A block of mass 15 kg is placed on a long trolley . The coefficient of

1.	A block of mass 15 kg is placed on a long trolley . The coefficient of friction between the block andthe trolley is 0.18. The trolley accelerates from rest with 0.5ms^(-2) for 20s and then moves with uniform velocity. Discuss the motion of theblock as viewed by (a) a stationary observer on theground (b) as observer moving with the trolley.
Answer» <html><body><p><br/></p>Solution :`F_(s)=mu_(s)N=mu_(s)mg=0.18xx15xx9.8=26.46N`. Force on block `=F=ma=15xx7.5=7.5N F_(s) <a href="https://interviewquestions.tuteehub.com/tag/gt-1013864" style="font-weight:bold;" target="_blank" title="Click to know more about GT">GT</a> F`.So the block cannot move. (a) The stationary <a href="https://interviewquestions.tuteehub.com/tag/observer-1127626" style="font-weight:bold;" target="_blank" title="Click to know more about OBSERVER">OBSERVER</a> will see the accelerated and the uniformmotion . (b) The observeris in an accelerated <a href="https://interviewquestions.tuteehub.com/tag/frame-998974" style="font-weight:bold;" target="_blank" title="Click to know more about FRAME">FRAME</a>. So laws of motion are not applicable. But during uniform motion, he will see that the block is at <a href="https://interviewquestions.tuteehub.com/tag/rest-11386" style="font-weight:bold;" target="_blank" title="Click to know more about REST">REST</a> w.r.t him.</body></html>