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A block of mass `m` lying on a horizontal plane , is acted upon by a horizontal force p and another force `Q` inclined at an angle `theta` to the vertical .The block will remain in equilibrium if the coefficient of friction between it and the surface is (assume `p gt Q)` A. `(P+Qsintheta)//(mg+Qcostheta)`B. `(Pcostheta+Q)//(mg-Qsintheta)`C. `(P+Qcostheta)//(mg+Qsintheta)`D. `(P sintheta-Q)-(mg-Qcostheta)` |
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Answer» Correct Answer - A Friction force `=mmuR=mu(mg+Qcostheta)` And horizontal push `=P+Qsintheta` For equilibrium, we have `mu(mg+Qcostheta)=P+Qsintheta` `mu=(P+Qsintheta)/(mg+Qcostheta)` |
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