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A block regulated by a seconds pendulum keeps correct time. During summer the length of the pendulum increases to 1.01 m How much will the clock gain or lose in one day?

Answer» <html><body><p></p>Solution :The time <a href="https://interviewquestions.tuteehub.com/tag/period-1151023" style="font-weight:bold;" target="_blank" title="Click to know more about PERIOD">PERIOD</a> of a simple pendulum is <br/> `T=2sqrt(l/<a href="https://interviewquestions.tuteehub.com/tag/g-1003017" style="font-weight:bold;" target="_blank" title="Click to know more about G">G</a>)=((2pi)/g)(l^(1//2))` <br/> differentiating T w.r.t l and dividing by T on both slides we get `(gT)/T=1/2(dl)/l` <br/> In case of a <a href="https://interviewquestions.tuteehub.com/tag/seconds-1198593" style="font-weight:bold;" target="_blank" title="Click to know more about SECONDS">SECONDS</a> pendulum T=2 s and <br/> `l=g/(pi^(2)0=0.9927m` <br/> Also `dl=1.01-0.9927=0.0173m` <br/>`:.(dT)/2=1/2(0.0173/0.9927)` <br/> i.e. The change in time period or change in time for 1 oscillation `dT=0.0173/0.9927s` <br/> `dT=1/2 (dl)/lT=1/2(dl)/l 86,400`<a href="https://interviewquestions.tuteehub.com/tag/per-590802" style="font-weight:bold;" target="_blank" title="Click to know more about PER">PER</a> day <br/> `=1/20.0173/0.9927xx86400=752.9s` <br/> When the length <a href="https://interviewquestions.tuteehub.com/tag/increases-1040626" style="font-weight:bold;" target="_blank" title="Click to know more about INCREASES">INCREASES</a> the time period of the pendulum increases. So the clock loses time or mass slow.</body></html>


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