A block regulated by a seconds pendulum keeps correct time. During summer the length of the pendulum increases to 1.01 m How much will the clock gain or lose in one day?

A block regulated by a seconds pendulum keeps correct time. During sum

1.	A block regulated by a seconds pendulum keeps correct time. During summer the length of the pendulum increases to 1.01 m How much will the clock gain or lose in one day?
Answer» Solution :The time PERIOD of a simple pendulum is `T=2sqrt(l/G)=((2pi)/g)(l^(1//2))` differentiating T w.r.t l and dividing by T on both slides we get `(gT)/T=1/2(dl)/l` In case of a SECONDS pendulum T=2 s and `l=g/(pi^(2)0=0.9927m` Also `dl=1.01-0.9927=0.0173m` `:.(dT)/2=1/2(0.0173/0.9927)` i.e. The change in time period or change in time for 1 oscillation `dT=0.0173/0.9927s` `dT=1/2 (dl)/lT=1/2(dl)/l 86,400`PER day `=1/20.0173/0.9927xx86400=752.9s` When the length INCREASES the time period of the pendulum increases. So the clock loses time or mass slow.