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A bob of mass m attached to an inextensible string of length l is suspended from a vertical support. The bob rotates in a horizontal circle withan angular speed omega rad/s about the vertical support. About the point of suspension |
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Answer» ANGULAR momentum is conserved Magnitude of the momentum `vec(p)` of the bob = `|vec(p)|`= mv = m`omega l` = constant As angular momentum `vec(L) = vec(r ) xx vec(p)` and the angle between `vec(r ) and vec(p)` is ALWAYS `90^(@)`. `|vec(L)| = l cdot m omega l cdot sin 90^(@) = m l^(2) omega` = constant ALSO, `vec(r)` is l aways radially outwards and `vec(p)` is TANGENTIAL. So `vec(L)` is always DIRECTED along the axis of rotation. So its direction is also fixed. |
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