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A body has a time period (4/5) s under the action of one force and (3/5) s under the action of another force. Then time period when both the forces are acting in the opposite direction simultaneously will beA. `4//5 s`B. `5//4 s`C. 1 sD. `12//5 sqrt(7) s` |
Answer» Correct Answer - D `F=F_(1)-F_(2)` `T^(2)prop(1)/(F) therefore Fprop(1)/(T^(2))` `T=(T_(1)T_(2))/(sqrt(T_(1)^(2)+T_(2)^(2)))=((4)/(5)xx(3)/(5))/(sqrt((16)/(25)-(9)/(25)))=((12)/(25))/((7)/(25))=(12)/(7)` |
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