1.

A body has a time period (4/5) s under the action of one force and (3/5) s under the action of another force. Then time period when both the forces are acting in the opposite direction simultaneously will beA. `4//5 s`B. `5//4 s`C. 1 sD. `12//5 sqrt(7) s`

Answer» Correct Answer - D
`F=F_(1)-F_(2)`
`T^(2)prop(1)/(F) therefore Fprop(1)/(T^(2))`
`T=(T_(1)T_(2))/(sqrt(T_(1)^(2)+T_(2)^(2)))=((4)/(5)xx(3)/(5))/(sqrt((16)/(25)-(9)/(25)))=((12)/(25))/((7)/(25))=(12)/(7)`


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