A body is moving indirectionally under the influence of a source of constant power . Its displacement in time t is proportional to

A body is moving indirectionally under the influence of a source of co

1.	A body is moving indirectionally under the influence of a source of constant power . Its displacement in time t is proportional to
Answer» <html><body><p>`t^(1/2)`<br/>t<br/>`t^(3/2)`<br/>`t^(2)`</p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :` :. W = Pt ` [ Work = Power `xx` Time]<br/> ` :. 1/2 mv^(2) = Pt [ :. W = <a href="https://interviewquestions.tuteehub.com/tag/k-527196" style="font-weight:bold;" target="_blank" title="Click to know more about K">K</a> - K_(0) " here "K_(0)=0] ` <br/> ` :. v =sqrt((2Pt)/m)` <br/> ` :. (dx)/(dt) =sqrt((2Pt)/m) ""( :. v =(dt)/dt)` <br/> Power P=Force F `xx` velocity v<br/> ` :. " P = ma " xx " at " [ :. " F = ma , v =at "]` <br/> ` :. P= ma^(2)t` <br/> ` :.a = sqrt(P/(mt))` <br/> Now, from equation (3) of motion of <a href="https://interviewquestions.tuteehub.com/tag/constant-930172" style="font-weight:bold;" target="_blank" title="Click to know more about CONSTANT">CONSTANT</a> acceleration, <br/> In `<a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a> = 1/2 sqrt(P/((mt))xxt^(2)` <br/> ` :. x = 1/2 sqrt(P/m)xxt^(3/2)` <br/> ` :. x prop t^(3/2) " " [ :. " P and m are constant"]`</body></html>