InterviewSolution
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InterviewSolution
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A body is moving vertically upwards under gravity such that its position from ground is given as `y=ut-(1)/(2)g t^(2)` . Find the max height reached by body. |
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Answer» `(dy)/(dt)=u-g t=0 ,t=(u)/(g)` `(d^(2)y)/(dx^(2))=-glt0` (which is negative). So we get maximum height`y_(max)at" " t=(u)/(g)sec`. `y_(max)=u((u)/(g))-(1)/(2)g((u)/(g))^(2)` `(u^(2))/(2g)` |
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