A body moving ina curved path possessesa velicty 3m//stowards north at any instant of its motion . A fter 10s, the velocity of the body was found to be 4 m//s towards west. Calculate the average acceleration during this interval .

A body moving ina curved path possessesa velicty 3m//stowards north at

1.	A body moving ina curved path possessesa velicty 3m//stowards north at any instant of its motion . A fter 10s, the velocity of the body was found to be 4 m//s towards west. Calculate the average acceleration during this interval .
Answer» Solution :To SOLVE this problem the vector nature of velocity must be TAKEN into account. In the figure, the initial velocity`v_(0)`and the final velocity v arfe DRAWN from a common origin . The vecto difference of them is found by the parallelogram method. The magnitude of difference is `\|v-v_(0)\|=OC=sqrt(OA^(2)+AC^(2))` `=sqrt(4^(2)+3^(2))=5m//s` The direction is given by `tan theta =3/4=0.75, theta =37^(0)` Average acceleration `=\|vecv-vecv_(0)\|/t=5/(10)=0.5m//s^(2)`at`37^(@)`south of WEST