A body of mass 0.5 kg travels in a straight line with velocity v = ax^(3/2) "where " a=5m^(-1/2)s^(-1) . What is the work done by the net force during its displacement from x = 0 to x = 2 m ?

A body of mass 0.5 kg travels in a straight line with velocity v = ax^

1.	A body of mass 0.5 kg travels in a straight line with velocity v = ax^(3/2) "where " a=5m^(-1/2)s^(-1) . What is the work done by the net force during its displacement from x = 0 to x = 2 m ?
Answer» <html><body><p></p>Solution :If a body <a href="https://interviewquestions.tuteehub.com/tag/undergoes-1436539" style="font-weight:bold;" target="_blank" title="Click to know more about UNDERGOES">UNDERGOES</a> displacement dx, then work done by the <a href="https://interviewquestions.tuteehub.com/tag/force-22342" style="font-weight:bold;" target="_blank" title="Click to know more about FORCE">FORCE</a> W = ma dx . <br/> ` :. W = m (dv)/(dt) .dx `<br/> `= m (dx)/(dt) .dv ` <br/> = mv dv<br/> ` :. W = int dW = m int_(<a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>)^(2) " v dv" =1/2 mv^(2)`<br/> ` = 1/2 m (ax^(3/2))_(0)^(2)` <br/> ` = 1/2 "ma"^(2)<a href="https://interviewquestions.tuteehub.com/tag/x-746616" style="font-weight:bold;" target="_blank" title="Click to know more about X">X</a>^(3)` <br/> ` = 1/2 xx 1/2 xx(5)^(2) xx(2)^(3)` <br/> = 50 <a href="https://interviewquestions.tuteehub.com/tag/j-520843" style="font-weight:bold;" target="_blank" title="Click to know more about J">J</a></body></html>