A body of mass 0.5 kg travels in a straight line with velocity v = ax^(3/2) "where " a=5m^(-1/2)s^(-1) . What is the work done by the net force during its displacement from x = 0 to x = 2 m ?

A body of mass 0.5 kg travels in a straight line with velocity v = ax^

1.	A body of mass 0.5 kg travels in a straight line with velocity v = ax^(3/2) "where " a=5m^(-1/2)s^(-1) . What is the work done by the net force during its displacement from x = 0 to x = 2 m ?
Answer» Solution :If a body UNDERGOES displacement dx, then work done by the FORCE W = ma dx . ` :. W = m (dv)/(dt) .dx ` `= m (dx)/(dt) .dv ` = mv dv ` :. W = int dW = m int_(0)^(2) " v dv" =1/2 mv^(2)` ` = 1/2 m (ax^(3/2))_(0)^(2)` ` = 1/2 "ma"^(2)X^(3)` ` = 1/2 xx 1/2 xx(5)^(2) xx(2)^(3)` = 50 J