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A body of mass 1 kg is thrown upwards with a velocity 20 ms^(-1) .It momentarily come to rest after attaining a height of 18 m . How much energy is lost due to air friction (g = 10 m//s^(-2))

Answer» <html><body><p>30 <a href="https://interviewquestions.tuteehub.com/tag/j-520843" style="font-weight:bold;" target="_blank" title="Click to know more about J">J</a> <br/>40 J <br/>10 J <br/>20 J </p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :When a body thrown <a href="https://interviewquestions.tuteehub.com/tag/upwards-2318352" style="font-weight:bold;" target="_blank" title="Click to know more about UPWARDS">UPWARDS</a> , its kinetic energy converted into <a href="https://interviewquestions.tuteehub.com/tag/potential-1161228" style="font-weight:bold;" target="_blank" title="Click to know more about POTENTIAL">POTENTIAL</a> energy and energy lost due to friction is equal to th difference between kinetic and potential energy .<br/> ` :. " Energy lost "= K - V ` <br/> ` = 1/2 mv^(2) -mgh` <br/> ` = 1/2 xx 1xx <a href="https://interviewquestions.tuteehub.com/tag/400-315233" style="font-weight:bold;" target="_blank" title="Click to know more about 400">400</a> -1 xx 10 xx 18` <br/> ` = 200 - 180 = 20 J `</body></html>


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