A body weighs 64 N on the surface of the Earth. What is the gravitational force on it (in N) due to the Earth at a height equal to one-third of the radius of the Earth?

A body weighs 64 N on the surface of the Earth. What is the gravitatio

1.	A body weighs 64 N on the surface of the Earth. What is the gravitational force on it (in N) due to the Earth at a height equal to one-third of the radius of the Earth?
Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/linear-1074458" style="font-weight:bold;" target="_blank" title="Click to know more about LINEAR">LINEAR</a> velocity v=72 km/h = `(72 xx 1000)/(60 xx 60) = 20` m/s <br/> Initial angular velocity of the wheel `=omega_(0) = v/r = 20/(0.25) = 80` rad/s <br/> Final angular velocity =`omega =0` <br/> Time =t= <a href="https://interviewquestions.tuteehub.com/tag/16s-277872" style="font-weight:bold;" target="_blank" title="Click to know more about 16S">16S</a> <br/>Angular <a href="https://interviewquestions.tuteehub.com/tag/acceleration-13745" style="font-weight:bold;" target="_blank" title="Click to know more about ACCELERATION">ACCELERATION</a> = `alpha` = ? <br/> `alpha = (omega-omega_(0))/t = (0-80)/16 = -<a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a> "rad"//s^(2)` <br/> Average torque `=tau = lalpha = 5 xx 5 = 25` Nm</body></html>