A bottle contains 82 gm of liquid of 10^(@)C. When it is heated to 35^(@)C, 2 gm of liquid is expelled. Calculate the apparent coefficient of expansion of liquid.

A bottle contains 82 gm of liquid of 10^(@)C. When it is heated to 35^

1.	A bottle contains 82 gm of liquid of 10^(@)C. When it is heated to 35^(@)C, 2 gm of liquid is expelled. Calculate the apparent coefficient of expansion of liquid.
Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :Mass of the <a href="https://interviewquestions.tuteehub.com/tag/liquid-1075124" style="font-weight:bold;" target="_blank" title="Click to know more about LIQUID">LIQUID</a> in the bottle `(m _(<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a>))= 82gm,` Mass of the luquid expelled `(m _(1) - m (2))= 2 <a href="https://interviewquestions.tuteehub.com/tag/gm-1008640" style="font-weight:bold;" target="_blank" title="Click to know more about GM">GM</a> ` <br/> Mass of the remaining `= 82-2 =80 gm,` Initial temperature `(t _(1)) = 10^(@)C` <br/> Final temperature `(t _(2)) = <a href="https://interviewquestions.tuteehub.com/tag/35-308504" style="font-weight:bold;" target="_blank" title="Click to know more about 35">35</a> ^(@)C,` Coefficient of apparent expansion <br/> `gamma _(a) = (m _(1) -m _(2))/( m _(2) (t _(2) - t _(1))) = (2)/( 80 ( 35 - 10)) = (2)/( 80 xx 25) = (2)/(2000) = 0.001 //^(@)C` <br/> `therefore gamma _(a) = 0.001 //^(@)C`</body></html>