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A boy after swimming comes out from a poolcovered with a film of waterweighing 80 g .How much heat must be suppliedto evaporate this water ? (Delta_(v) H^(@)=40.79 kJmol^(-1))

Answer» <html><body><p>`1.61 xx10^(2) <a href="https://interviewquestions.tuteehub.com/tag/kj-1063034" style="font-weight:bold;" target="_blank" title="Click to know more about KJ">KJ</a>`<br/>`1.71 xx 10^(2)kJ`<br/>` 1.81xx10^(2) kJ `<br/>` 1.91 xx 10^(2) kJ `</p>Solution :Given `: Delta_("vap") <a href="https://interviewquestions.tuteehub.com/tag/h-1014193" style="font-weight:bold;" target="_blank" title="Click to know more about H">H</a>^(@) `for`H_(2)O= 40.79 kJ mol^(-1)` <br/> <a href="https://interviewquestions.tuteehub.com/tag/water-1449333" style="font-weight:bold;" target="_blank" title="Click to know more about WATER">WATER</a> to be evaporated`= <a href="https://interviewquestions.tuteehub.com/tag/80-337972" style="font-weight:bold;" target="_blank" title="Click to know more about 80">80</a> g( 80)/( 18) <a href="https://interviewquestions.tuteehub.com/tag/mole-1100299" style="font-weight:bold;" target="_blank" title="Click to know more about MOLE">MOLE</a>` <br/> `=4.44` mole <br/> Heat required for evaporated of 1 moleof `H_(2)O =40.79kJ` <br/> `:. `Heat required for evaporated of 4.44 moleof`H_(2)O=40.79 xx 4.44 = 1.81 xx 10^(2) kJ`</body></html>


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