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A boy after swimming comes out from a poolcovered with a film of waterweighing 80 g .How much heat must be suppliedto evaporate this water ? (Delta_(v) H^(@)=40.79 kJmol^(-1)) |
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Answer» `1.61 xx10^(2) KJ` WATER to be evaporated`= 80 g( 80)/( 18) MOLE` `=4.44` mole Heat required for evaporated of 1 moleof `H_(2)O =40.79kJ` `:. `Heat required for evaporated of 4.44 moleof`H_(2)O=40.79 xx 4.44 = 1.81 xx 10^(2) kJ` |
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