1.

A boy after swimming comes out from a poolcovered with a film of waterweighing 80 g .How much heat must be suppliedto evaporate this water ? (Delta_(v) H^(@)=40.79 kJmol^(-1))

Answer»

`1.61 xx10^(2) KJ`
`1.71 xx 10^(2)kJ`
` 1.81xx10^(2) kJ `
` 1.91 xx 10^(2) kJ `

Solution :Given `: Delta_("vap") H^(@) `for`H_(2)O= 40.79 kJ mol^(-1)`
WATER to be evaporated`= 80 g( 80)/( 18) MOLE`
`=4.44` mole
Heat required for evaporated of 1 moleof `H_(2)O =40.79kJ`
`:. `Heat required for evaporated of 4.44 moleof`H_(2)O=40.79 xx 4.44 = 1.81 xx 10^(2) kJ`


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