A+BrarrC+D, DeltaH=-10.000Jmol^(-1),DeltaS=-33.3mol^(-1)K^(-1) (i) At what temperature the reaction will occur spontaneously from left to right? (ii) At what temperature, the reaction will reverse?

A+BrarrC+D, DeltaH=-10.000Jmol^(-1),DeltaS=-33.3mol^(-1)K^(-1) (i) A

1.	A+BrarrC+D, DeltaH=-10.000Jmol^(-1),DeltaS=-33.3mol^(-1)K^(-1) (i) At what temperature the reaction will occur spontaneously from left to right? (ii) At what temperature, the reaction will reverse?
Answer» SOLUTION :`DeltaG=DeltaH-TDeltaS` At equilibrium, `DeltaG=0` so that `DeltaH=TDeltaS` (or) `T=(DeltaH)/(DeltaS)=(-10000Jmol^(-1))/(-33.3Jmol^(-1))=300.3K` (i) For spontaneity from left to RIGHT, `DeltaG` should be -ve for the given reaction. This will be so if `Tlt300.3K` (ii) For reverse reaction OT OCCUR. `DeltaG` should be `+ve` for FORWARD reaction. This will be so if `Tgt300.3K`.