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A+BrarrC+D, DeltaH=-10.000Jmol^(-1),DeltaS=-33.3mol^(-1)K^(-1) (i) At what temperature the reaction will occur spontaneously from left to right? (ii) At what temperature, the reaction will reverse? |
Answer» <html><body><p></p><a href="https://interviewquestions.tuteehub.com/tag/solution-25781" style="font-weight:bold;" target="_blank" title="Click to know more about SOLUTION">SOLUTION</a> :`DeltaG=DeltaH-TDeltaS` At equilibrium, `DeltaG=0` so that <br/> `DeltaH=TDeltaS` (or) <br/> `T=(DeltaH)/(DeltaS)=(-10000Jmol^(-1))/(-33.3Jmol^(-1))=300.3K` <br/> (i) For spontaneity from left to <a href="https://interviewquestions.tuteehub.com/tag/right-1188951" style="font-weight:bold;" target="_blank" title="Click to know more about RIGHT">RIGHT</a>, `DeltaG` should be -ve for the given reaction. This will be so if `Tlt300.3K` <br/> (ii) For reverse reaction <a href="https://interviewquestions.tuteehub.com/tag/ot-584155" style="font-weight:bold;" target="_blank" title="Click to know more about OT">OT</a> <a href="https://interviewquestions.tuteehub.com/tag/occur-583012" style="font-weight:bold;" target="_blank" title="Click to know more about OCCUR">OCCUR</a>. `DeltaG` should be `+ve` for <a href="https://interviewquestions.tuteehub.com/tag/forward-464460" style="font-weight:bold;" target="_blank" title="Click to know more about FORWARD">FORWARD</a> reaction. This will be so if `Tgt300.3K`.</body></html> | |