A brominated alkane an analysis gave 12.8% carbon and 2.1%H. If its vapour density is 93.95, what is its molecular formula?

A brominated alkane an analysis gave 12.8% carbon and 2.1%H. If its va

1.	A brominated alkane an analysis gave 12.8% carbon and 2.1%H. If its vapour density is 93.95, what is its molecular formula?
Answer» <html><body><p></p>Solution :<a href="https://interviewquestions.tuteehub.com/tag/percent-1150333" style="font-weight:bold;" target="_blank" title="Click to know more about PERCENT">PERCENT</a> weight of bromium = 100-(%C+%H) = 100-14.9 = 85.<a href="https://interviewquestions.tuteehub.com/tag/1-256655" style="font-weight:bold;" target="_blank" title="Click to know more about 1">1</a> <br/> C : H: Br `=(12.8)/(12) : (<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>.1)/(1) : (85.1)/(80) = 1 : 2 : 1 ` <br/> Empirical formula is `CH_(2)Br` <br/> Molecular weight `= 2xxV.D. = 2xx93.95 = 187.9` <br/> ` n = (187.9)/(<a href="https://interviewquestions.tuteehub.com/tag/94-342308" style="font-weight:bold;" target="_blank" title="Click to know more about 94">94</a>) = 2` <br/> Molecular formula `=2xxCH_(2)Br = C_(2)H_(4)Br_(2)`</body></html>