A buffer solution 0.04 M in Na_2HPO_4 and 0.02M in Na_3 PO_4 is prepared. The electrolytic oxidation of 1.0 milli -mole of the organic compound RNHOH is carried out in 100 mLof the buffer. The reaction is RNHOH +H_2O to RNO_2 +4H ^(+) + 4e ^(-) The approximatepH of solution after the oxidation is complete is:[Given : forH_3O PO_4, pK_(a_1)=7.20 , pK_(a_2) =12]

A buffer solution 0.04 M in Na_2HPO_4 and 0.02M in Na_3 PO_4 is prepar

1.	A buffer solution 0.04 M in Na_2HPO_4 and 0.02M in Na_3 PO_4 is prepared. The electrolytic oxidation of 1.0 milli -mole of the organic compound RNHOH is carried out in 100 mLof the buffer. The reaction is RNHOH +H_2O to RNO_2 +4H ^(+) + 4e ^(-) The approximatepH of solution after the oxidation is complete is:[Given : forH_3O PO_4, pK_(a_1)=7.20 , pK_(a_2) =12]
Answer» <html><body><p>` 6.90 ` <br/>` <a href="https://interviewquestions.tuteehub.com/tag/7-332378" style="font-weight:bold;" target="_blank" title="Click to know more about 7">7</a>.20 ` <br/>` 7. <a href="https://interviewquestions.tuteehub.com/tag/5-319454" style="font-weight:bold;" target="_blank" title="Click to know more about 5">5</a>` <br/>None of these </p>Solution :` {:(PO_4^(3-)+,H^(+)to, HPO_4^(-2)),( <a href="https://interviewquestions.tuteehub.com/tag/0-251616" style="font-weight:bold;" target="_blank" title="Click to know more about 0">0</a>.02M , 0.04 M , 0.04 M),( -, 0.02 , 0.06M), (- , 0.02M, -):}` <br/> ` {:( HPO_4^(-2) ,H^(+) to, H_2PO_4^(-)),( 0.06, 0.02 , 0),( 0.02 , - , 0.02M),( 0.04M, , ):}` <br/> ` pH =7.2 +<a href="https://interviewquestions.tuteehub.com/tag/log-543719" style="font-weight:bold;" target="_blank" title="Click to know more about LOG">LOG</a> ""(0.04)/(0.02 )=7.5`</body></html>