A buffer solution contains 0.1 mole of sodium acetate in 1000 cm^(3) of 0.1 M acetic acid. To the above buffer solution, 0.1 M aceticacid. To the above buffer solution, 0.1 mole of sodium acetate is further added and dissolved. The pH of the resultingbuffer is equal to ...........

A buffer solution contains 0.1 mole of sodium acetate in 1000 cm^(3) o

1.	A buffer solution contains 0.1 mole of sodium acetate in 1000 cm^(3) of 0.1 M acetic acid. To the above buffer solution, 0.1 M aceticacid. To the above buffer solution, 0.1 mole of sodium acetate is further added and dissolved. The pH of the resultingbuffer is equal to ...........
Answer» <html><body><p>`pK_(a) - log2`<br/>`pK_(a)`<br/>`pK_(a)+<a href="https://interviewquestions.tuteehub.com/tag/2-283658" style="font-weight:bold;" target="_blank" title="Click to know more about 2">2</a>`<br/>`pK_(a)+<a href="https://interviewquestions.tuteehub.com/tag/log-543719" style="font-weight:bold;" target="_blank" title="Click to know more about LOG">LOG</a> 2`</p>Solution :`pH = pK_(a) + log.(["Salt"])/(["Acid"])` <br/> [Salt]`=(0.1+0.1"mole")/(1000 <a href="https://interviewquestions.tuteehub.com/tag/ml-548251" style="font-weight:bold;" target="_blank" title="Click to know more about ML">ML</a>) = (0.2"mole")/(<a href="https://interviewquestions.tuteehub.com/tag/1l-282810" style="font-weight:bold;" target="_blank" title="Click to know more about 1L">1L</a>) = 0.2M` <br/> [Acid]`=(0.1 "mole")/(1000mL) = (0.1"mole")/(1L)=0.1 M` <br/> `:. pH = pK_(a) + log 2`.</body></html>