A buffer solution of pH = 4.7 is prepared from CH_(3)COONa and CH_(3)COOH. Dissociation constant of acetic acid is 1.75xx10^(-5). Calculate the mole proportion of sodium acetate and acetic acid.

A buffer solution of pH = 4.7 is prepared from CH_(3)COONa and CH_(3)C

1.	A buffer solution of pH = 4.7 is prepared from CH_(3)COONa and CH_(3)COOH. Dissociation constant of acetic acid is 1.75xx10^(-5). Calculate the mole proportion of sodium acetate and acetic acid.
Answer» Solution :`pH=pK_(a)+"log"(["SALT"])/(["Acid"])rArrpH=-log_(10)K_(a)+"log"([CH_(3)COONa])/([CH_(3)COOH])` `4.7=-log_(10)(1.75xx10^(-5))+"log"([CH_(3)COONa])/([CH_(3)COOH])` `4.7=5-log1.75+"log"([CH_(3)COONa])/([CH_(3)COOH])=5-0.2430+"log"([CH_(3)COONa])/([CH_(3)COOH])` `"log"([CH_(3)COONa])/([CH_(3)COOH])="anti"log(-0.0557)="anti"log(-0.057+1-1)` `([CH_(3)COONa])/([CH_(3)COOH])=0.8770`.