A buffer solution with pH 9 is to be prepared by mixing NH_(4) Cl and NH_(4)OH. Calculate the number of moles of NH_(4)Cl that should be added to one litre of 1.0 M NH_(4)OH (K_(b)=1.8xx10^(-5))

A buffer solution with pH 9 is to be prepared by mixing NH_(4) Cl and

1.	A buffer solution with pH 9 is to be prepared by mixing NH_(4) Cl and NH_(4)OH. Calculate the number of moles of NH_(4)Cl that should be added to one litre of 1.0 M NH_(4)OH (K_(b)=1.8xx10^(-5))
Answer» <html><body><p></p>Solution :For a <a href="https://interviewquestions.tuteehub.com/tag/basic-15343" style="font-weight:bold;" target="_blank" title="Click to know more about BASIC">BASIC</a> <a href="https://interviewquestions.tuteehub.com/tag/buffer-905159" style="font-weight:bold;" target="_blank" title="Click to know more about BUFFER">BUFFER</a>, `pOH = pK_(b)+log.(["<a href="https://interviewquestions.tuteehub.com/tag/salt-1193804" style="font-weight:bold;" target="_blank" title="Click to know more about SALT">SALT</a>"])/(["Base"])` <br/> Further, `pH + pOH = 14 ` so that `pOH = 14 - pH = 14 - 9 = 5` <br/> `pK_(b)=-log K_(b) = - log(1.8xx10^(-5))=4.7447` <br/> [Base] `=[NH_(4)OH]= 1 "<a href="https://interviewquestions.tuteehub.com/tag/mol-1100196" style="font-weight:bold;" target="_blank" title="Click to know more about MOL">MOL</a>" L^(-1)` <br/> `:. 5 = 4. 7447 + log. (["Salt"])/(1) or log ["Salt"] = 0.2553 or ["Salt"]= 1.8 "mol" L^(-1)`</body></html>